In #Laws #of #Indices, a number to a negative index or exponent is expressed as a reciprocal of the number a positive common exponent. Mathematically; a⁻ⁿ = 1/aⁿ for a and n not equal to zero In this video I'm going to prove this law for you. If you find this video interesting, kindly subscribe to my channel for more exciting Maths tutorials. Subscribe link: Facebook: Instagram: Linkedin: Blog:
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INDICES AND LOGARITHMS
2020
R
4 h 32 m
نيجيريا
الرياضيات
In #Laws #of #Indices, a number to a negative index or exponent is expressed as a reciprocal of the number a positive common exponent. Mathematically; a⁻ⁿ = 1/aⁿ for a and n not equal to zero In this video I'm going to prove this law for you. If you find this video interesting, kindly subscribe to my channel for more exciting Maths tutorials. Subscribe link: Facebook: Instagram: Linkedin: Blog:
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شاهد أونلاين
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Adderael
22/10/2025 07:45
Proving x⁰=1 Logically.
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22/10/2025 07:45
Proving x⁰=1 Logically.
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22/10/2025 07:45
Simple Logarithmic Equation
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Simple Logarithmic Equation
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Exponential Equation 3ˣ+9ˣ=27ˣ
Baba Bocoum
22/10/2025 07:45
Exponential Equation 3ˣ+9ˣ=27ˣ
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22/10/2025 07:45
Exponential Equation | e^2x + 2e^x - 15 = 0
الفاسي 🖤💛
22/10/2025 07:45
Exponential Equation | e^2x + 2e^x - 15 = 0
K_drama
22/10/2025 07:45
Exponential Equation | x^(x•x^½)=(x•x^½)^x
•°Random.Weeb°•√
22/10/2025 07:45
Exponential Equation | x^(x•x^½)=(x•x^½)^x
تقييمات المستخدمين
Adderael
22/10/2025 07:45
Proving x⁰=1 Logically.
M 2bosha3lah👌🔥
22/10/2025 07:45
Proving x⁰=1 Logically.
Maelyse Mondesir
22/10/2025 07:45
Simple Logarithmic Equation
user9585433821270
22/10/2025 07:45
Simple Logarithmic Equation
Bad chatty ⚡️
22/10/2025 07:45
Exponential Equation 3ˣ+9ˣ=27ˣ
Baba Bocoum
22/10/2025 07:45
Exponential Equation 3ˣ+9ˣ=27ˣ
Wesley Lots
22/10/2025 07:45
Exponential Equation | e^2x + 2e^x - 15 = 0
الفاسي 🖤💛
22/10/2025 07:45
Exponential Equation | e^2x + 2e^x - 15 = 0
K_drama
22/10/2025 07:45
Exponential Equation | x^(x•x^½)=(x•x^½)^x
•°Random.Weeb°•√
22/10/2025 07:45
Exponential Equation | x^(x•x^½)=(x•x^½)^x
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